-3(y+3)=4y-1+2(4y+5)

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Solution for -3(y+3)=4y-1+2(4y+5) equation: 



-3(y+3)=4y-1+2(4y+5)

We move all terms to the left:

-3(y+3)-(4y-1+2(4y+5))=0

We multiply parentheses

-3y-(4y-1+2(4y+5))-9=0



We calculate terms in parentheses: -(4y-1+2(4y+5)), so:

4y-1+2(4y+5)

determiningTheFunctionDomain
4y+2(4y+5)-1

We multiply parentheses

4y+8y+10-1

We add all the numbers together, and all the variables

12y+9

Back to the equation:

-(12y+9)



We get rid of parentheses

-3y-12y-9-9=0

We add all the numbers together, and all the variables

-15y-18=0

We move all terms containing y to the left, all other terms to the right

-15y=18

y=18/-15

y=-1+1/5

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