-3(y+3)=5y-7+4(2y+1)

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Solution for -3(y+3)=5y-7+4(2y+1) equation: 



-3(y+3)=5y-7+4(2y+1)

We move all terms to the left:

-3(y+3)-(5y-7+4(2y+1))=0

We multiply parentheses

-3y-(5y-7+4(2y+1))-9=0



We calculate terms in parentheses: -(5y-7+4(2y+1)), so:

5y-7+4(2y+1)

determiningTheFunctionDomain
5y+4(2y+1)-7

We multiply parentheses

5y+8y+4-7

We add all the numbers together, and all the variables

13y-3

Back to the equation:

-(13y-3)



We get rid of parentheses

-3y-13y+3-9=0

We add all the numbers together, and all the variables

-16y-6=0

We move all terms containing y to the left, all other terms to the right

-16y=6

y=6/-16

y=-3/8

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