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-3(y+3)=5y-9+2(3y+8)
We move all terms to the left:
-3(y+3)-(5y-9+2(3y+8))=0
We multiply parentheses
-3y-(5y-9+2(3y+8))-9=0
We calculate terms in parentheses: -(5y-9+2(3y+8)), so:We get rid of parentheses
5y-9+2(3y+8)
determiningTheFunctionDomain 5y+2(3y+8)-9
We multiply parentheses
5y+6y+16-9
We add all the numbers together, and all the variables
11y+7
Back to the equation:
-(11y+7)
-3y-11y-7-9=0
We add all the numbers together, and all the variables
-14y-16=0
We move all terms containing y to the left, all other terms to the right
-14y=16
y=16/-14
y=-1+1/7
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