-3(y+3)=9y-9+2(3y+5)

Solution for -3(y+3)=9y-9+2(3y+5) equation:

-3(y+3)=9y-9+2(3y+5)

We move all terms to the left:

-3(y+3)-(9y-9+2(3y+5))=0

We multiply parentheses

-3y-(9y-9+2(3y+5))-9=0


We calculate terms in parentheses: -(9y-9+2(3y+5)), so:

9y-9+2(3y+5)

determiningTheFunctionDomain
9y+2(3y+5)-9

We multiply parentheses

9y+6y+10-9

We add all the numbers together, and all the variables

15y+1

Back to the equation:

-(15y+1)


We get rid of parentheses

-3y-15y-1-9=0

We add all the numbers together, and all the variables

-18y-10=0

We move all terms containing y to the left, all other terms to the right

-18y=10

y=10/-18

y=-5/9