-3(y+3)=y-3+4(3y+3)

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Solution for -3(y+3)=y-3+4(3y+3) equation: 



-3(y+3)=y-3+4(3y+3)

We move all terms to the left:

-3(y+3)-(y-3+4(3y+3))=0

We multiply parentheses

-3y-(y-3+4(3y+3))-9=0



We calculate terms in parentheses: -(y-3+4(3y+3)), so:

y-3+4(3y+3)

determiningTheFunctionDomain
y+4(3y+3)-3

We multiply parentheses

y+12y+12-3

We add all the numbers together, and all the variables

13y+9

Back to the equation:

-(13y+9)



We get rid of parentheses

-3y-13y-9-9=0

We add all the numbers together, and all the variables

-16y-18=0

We move all terms containing y to the left, all other terms to the right

-16y=18

y=18/-16

y=-1+1/8

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