-3(y+4)=4y-40

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Solution for -3(y+4)=4y-40 equation: 



-3(y+4)=4y-40

We move all terms to the left:

-3(y+4)-(4y-40)=0

We multiply parentheses

-3y-(4y-40)-12=0

We get rid of parentheses

-3y-4y+40-12=0

We add all the numbers together, and all the variables

-7y+28=0

We move all terms containing y to the left, all other terms to the right

-7y=-28

y=-28/-7

y=+4

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