-3(y+4)=5y-4+2(5y+1)

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Solution for -3(y+4)=5y-4+2(5y+1) equation: 



-3(y+4)=5y-4+2(5y+1)

We move all terms to the left:

-3(y+4)-(5y-4+2(5y+1))=0

We multiply parentheses

-3y-(5y-4+2(5y+1))-12=0



We calculate terms in parentheses: -(5y-4+2(5y+1)), so:

5y-4+2(5y+1)

determiningTheFunctionDomain
5y+2(5y+1)-4

We multiply parentheses

5y+10y+2-4

We add all the numbers together, and all the variables

15y-2

Back to the equation:

-(15y-2)



We get rid of parentheses

-3y-15y+2-12=0

We add all the numbers together, and all the variables

-18y-10=0

We move all terms containing y to the left, all other terms to the right

-18y=10

y=10/-18

y=-5/9

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