-3(y+4)=y-2+2(5y+3)

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Solution for -3(y+4)=y-2+2(5y+3) equation: 



-3(y+4)=y-2+2(5y+3)

We move all terms to the left:

-3(y+4)-(y-2+2(5y+3))=0

We multiply parentheses

-3y-(y-2+2(5y+3))-12=0



We calculate terms in parentheses: -(y-2+2(5y+3)), so:

y-2+2(5y+3)

determiningTheFunctionDomain
y+2(5y+3)-2

We multiply parentheses

y+10y+6-2

We add all the numbers together, and all the variables

11y+4

Back to the equation:

-(11y+4)



We get rid of parentheses

-3y-11y-4-12=0

We add all the numbers together, and all the variables

-14y-16=0

We move all terms containing y to the left, all other terms to the right

-14y=16

y=16/-14

y=-1+1/7

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