-3(y+5)=y-8+2(7y+1)

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Solution for -3(y+5)=y-8+2(7y+1) equation: 



-3(y+5)=y-8+2(7y+1)

We move all terms to the left:

-3(y+5)-(y-8+2(7y+1))=0

We multiply parentheses

-3y-(y-8+2(7y+1))-15=0



We calculate terms in parentheses: -(y-8+2(7y+1)), so:

y-8+2(7y+1)

determiningTheFunctionDomain
y+2(7y+1)-8

We multiply parentheses

y+14y+2-8

We add all the numbers together, and all the variables

15y-6

Back to the equation:

-(15y-6)



We get rid of parentheses

-3y-15y+6-15=0

We add all the numbers together, and all the variables

-18y-9=0

We move all terms containing y to the left, all other terms to the right

-18y=9

y=9/-18

y=-1/2

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