-3(y-2)+5=7(y-4)-1

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Solution for -3(y-2)+5=7(y-4)-1 equation: 



-3(y-2)+5=7(y-4)-1

We move all terms to the left:

-3(y-2)+5-(7(y-4)-1)=0

We multiply parentheses

-3y-(7(y-4)-1)+6+5=0



We calculate terms in parentheses: -(7(y-4)-1), so:

7(y-4)-1

We multiply parentheses

7y-28-1

We add all the numbers together, and all the variables

7y-29

Back to the equation:

-(7y-29)



We add all the numbers together, and all the variables

-3y-(7y-29)+11=0

We get rid of parentheses

-3y-7y+29+11=0

We add all the numbers together, and all the variables

-10y+40=0

We move all terms containing y to the left, all other terms to the right

-10y=-40

y=-40/-10

y=+4

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