-3(y-2)-5y=-2y(y+3)

Solution for -3(y-2)-5y=-2y(y+3) equation:

-3(y-2)-5y=-2y(y+3)

We move all terms to the left:

-3(y-2)-5y-(-2y(y+3))=0

We add all the numbers together, and all the variables

-5y-3(y-2)-(-2y(y+3))=0

We multiply parentheses

-5y-3y-(-2y(y+3))+6=0


We calculate terms in parentheses: -(-2y(y+3)), so:

-2y(y+3)

We multiply parentheses

-2y^2-6y

Back to the equation:

-(-2y^2-6y)


We add all the numbers together, and all the variables

-(-2y^2-6y)-8y+6=0

We get rid of parentheses

2y^2+6y-8y+6=0

We add all the numbers together, and all the variables

2y^2-2y+6=0

a = 2; b = -2; c = +6;
Δ = b2-4ac
Δ = -22-4·2·6
Δ = -44
Delta is less than zero, so there is no solution for the equation