-3(y-2)=-3y+6

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Solution for -3(y-2)=-3y+6 equation: 



-3(y-2)=-3y+6

We move all terms to the left:

-3(y-2)-(-3y+6)=0

We multiply parentheses

-3y-(-3y+6)+6=0

We get rid of parentheses

-3y+3y-6+6=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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