-3(y-2)=12

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Solution for -3(y-2)=12 equation: 



-3(y-2)=12

We move all terms to the left:

-3(y-2)-(12)=0

We multiply parentheses

-3y+6-12=0

We add all the numbers together, and all the variables

-3y-6=0

We move all terms containing y to the left, all other terms to the right

-3y=6

y=6/-3

y=-2

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