-3(y-2)=5(2y+1)

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Solution for -3(y-2)=5(2y+1) equation: 



-3(y-2)=5(2y+1)

We move all terms to the left:

-3(y-2)-(5(2y+1))=0

We multiply parentheses

-3y-(5(2y+1))+6=0



We calculate terms in parentheses: -(5(2y+1)), so:

5(2y+1)

We multiply parentheses

10y+5

Back to the equation:

-(10y+5)



We get rid of parentheses

-3y-10y-5+6=0

We add all the numbers together, and all the variables

-13y+1=0

We move all terms containing y to the left, all other terms to the right

-13y=-1

y=-1/-13

y=1/13

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