-3(y-2y)+2=-4(4y-4)+6+14y

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Solution for -3(y-2y)+2=-4(4y-4)+6+14y equation: 



-3(y-2y)+2=-4(4y-4)+6+14y

We move all terms to the left:

-3(y-2y)+2-(-4(4y-4)+6+14y)=0

We add all the numbers together, and all the variables

-3(-1y)-(-4(4y-4)+6+14y)+2=0

We multiply parentheses

3y-(-4(4y-4)+6+14y)+2=0



We calculate terms in parentheses: -(-4(4y-4)+6+14y), so:

-4(4y-4)+6+14y

determiningTheFunctionDomain
-4(4y-4)+14y+6

We add all the numbers together, and all the variables

14y-4(4y-4)+6

We multiply parentheses

14y-16y+16+6

We add all the numbers together, and all the variables

-2y+22

Back to the equation:

-(-2y+22)



We get rid of parentheses

3y+2y-22+2=0

We add all the numbers together, and all the variables

5y-20=0

We move all terms containing y to the left, all other terms to the right

5y=20

y=20/5

y=4

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