-3(y-2y)+8=-3(4y-y)+2+11y

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Solution for -3(y-2y)+8=-3(4y-y)+2+11y equation: 



-3(y-2y)+8=-3(4y-y)+2+11y

We move all terms to the left:

-3(y-2y)+8-(-3(4y-y)+2+11y)=0

We add all the numbers together, and all the variables

-3(-1y)-(-3(+3y)+2+11y)+8=0

We multiply parentheses

3y-(-3(+3y)+2+11y)+8=0



We calculate terms in parentheses: -(-3(+3y)+2+11y), so:

-3(+3y)+2+11y

determiningTheFunctionDomain
-3(+3y)+11y+2

We add all the numbers together, and all the variables

11y-3(+3y)+2

We multiply parentheses

11y-9y+2

We add all the numbers together, and all the variables

2y+2

Back to the equation:

-(2y+2)



We get rid of parentheses

3y-2y-2+8=0

We add all the numbers together, and all the variables

y+6=0

We move all terms containing y to the left, all other terms to the right

y=-6

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