-3(y-3)=6y+27

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Solution for -3(y-3)=6y+27 equation:



-3(y-3)=6y+27
We move all terms to the left:
-3(y-3)-(6y+27)=0
We multiply parentheses
-3y-(6y+27)+9=0
We get rid of parentheses
-3y-6y-27+9=0
We add all the numbers together, and all the variables
-9y-18=0
We move all terms containing y to the left, all other terms to the right
-9y=18
y=18/-9
y=-2

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