-3(y-3y)+4=-4(3y-y)+16+13y

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Solution for -3(y-3y)+4=-4(3y-y)+16+13y equation:


-3 (y-3y)+4=-4 (3y-y)+16+13y

We simplify the equation to the form, which is simple to understand 
-3(y-3y)+4=-4(3y-y)+16+13y

Simplifying terms in parentheses
-3*(-2y)+4=-4*(3y-y)+16+13y

Simplifying terms in parentheses
-3*(-2y)+4=-4*(+2y)+16+13y

Reorder the terms in parentheses
+(+6y)+4=-4*(+2y)+16+13y

Remove unnecessary parentheses
+6y+4=-4+*(+2y+)+16+13y

Reorder the terms in parentheses
+6y+4=+(-8y)+16+13y

Remove unnecessary parentheses
+6y+4=-8y+16+13y

We move all terms containing y to the left and all other terms to the right. 
+6y+8y-13y=+16-4

We simplify left and right side of the equation. 
+1y=+12

We divide both sides of the equation by 1 to get y. 
y=12

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