-3(y-4)+6=6y-4

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Solution for -3(y-4)+6=6y-4 equation: 



-3(y-4)+6=6y-4

We move all terms to the left:

-3(y-4)+6-(6y-4)=0

We multiply parentheses

-3y-(6y-4)+12+6=0

We get rid of parentheses

-3y-6y+4+12+6=0

We add all the numbers together, and all the variables

-9y+22=0

We move all terms containing y to the left, all other terms to the right

-9y=-22

y=-22/-9

y=2+4/9

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