-3(y-4)=2(2+y)

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Solution for -3(y-4)=2(2+y) equation: 



-3(y-4)=2(2+y)

We move all terms to the left:

-3(y-4)-(2(2+y))=0

We add all the numbers together, and all the variables

-3(y-4)-(2(y+2))=0

We multiply parentheses

-3y-(2(y+2))+12=0



We calculate terms in parentheses: -(2(y+2)), so:

2(y+2)

We multiply parentheses

2y+4

Back to the equation:

-(2y+4)



We get rid of parentheses

-3y-2y-4+12=0

We add all the numbers together, and all the variables

-5y+8=0

We move all terms containing y to the left, all other terms to the right

-5y=-8

y=-8/-5

y=1+3/5

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