-3(y-4)=6y-42

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Solution for -3(y-4)=6y-42 equation: 



-3(y-4)=6y-42

We move all terms to the left:

-3(y-4)-(6y-42)=0

We multiply parentheses

-3y-(6y-42)+12=0

We get rid of parentheses

-3y-6y+42+12=0

We add all the numbers together, and all the variables

-9y+54=0

We move all terms containing y to the left, all other terms to the right

-9y=-54

y=-54/-9

y=+6

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