-3(y-4)=7y+42

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Solution for -3(y-4)=7y+42 equation: 



-3(y-4)=7y+42

We move all terms to the left:

-3(y-4)-(7y+42)=0

We multiply parentheses

-3y-(7y+42)+12=0

We get rid of parentheses

-3y-7y-42+12=0

We add all the numbers together, and all the variables

-10y-30=0

We move all terms containing y to the left, all other terms to the right

-10y=30

y=30/-10

y=-3

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