-3(y-4y)+4=-3(3y-y)+3+14y

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Solution for -3(y-4y)+4=-3(3y-y)+3+14y equation: 



-3(y-4y)+4=-3(3y-y)+3+14y

We move all terms to the left:

-3(y-4y)+4-(-3(3y-y)+3+14y)=0

We add all the numbers together, and all the variables

-3(-3y)-(-3(+2y)+3+14y)+4=0

We multiply parentheses

9y-(-3(+2y)+3+14y)+4=0



We calculate terms in parentheses: -(-3(+2y)+3+14y), so:

-3(+2y)+3+14y

determiningTheFunctionDomain
-3(+2y)+14y+3

We add all the numbers together, and all the variables

14y-3(+2y)+3

We multiply parentheses

14y-6y+3

We add all the numbers together, and all the variables

8y+3

Back to the equation:

-(8y+3)



We get rid of parentheses

9y-8y-3+4=0

We add all the numbers together, and all the variables

y+1=0

We move all terms containing y to the left, all other terms to the right

y=-1

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