-3(y-4y)+7=-2(2y-y)+3+10y

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Solution for -3(y-4y)+7=-2(2y-y)+3+10y equation: 



-3(y-4y)+7=-2(2y-y)+3+10y

We move all terms to the left:

-3(y-4y)+7-(-2(2y-y)+3+10y)=0

We add all the numbers together, and all the variables

-3(-3y)-(-2(+y)+3+10y)+7=0

We multiply parentheses

9y-(-2(+y)+3+10y)+7=0



We calculate terms in parentheses: -(-2(+y)+3+10y), so:

-2(+y)+3+10y

determiningTheFunctionDomain
-2(+y)+10y+3

We add all the numbers together, and all the variables

10y-2(+y)+3

We multiply parentheses

10y-2y+3

We add all the numbers together, and all the variables

8y+3

Back to the equation:

-(8y+3)



We get rid of parentheses

9y-8y-3+7=0

We add all the numbers together, and all the variables

y+4=0

We move all terms containing y to the left, all other terms to the right

y=-4

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