-3(y-5)=6(-2y+-2)

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Solution for -3(y-5)=6(-2y+-2) equation: 



-3(y-5)=6(-2y+-2)

We move all terms to the left:

-3(y-5)-(6(-2y+-2))=0

We add all the numbers together, and all the variables

-3(y-5)-(6(-2y-2))=0

We multiply parentheses

-3y-(6(-2y-2))+15=0



We calculate terms in parentheses: -(6(-2y-2)), so:

6(-2y-2)

We multiply parentheses

-12y-12

Back to the equation:

-(-12y-12)



We get rid of parentheses

-3y+12y+12+15=0

We add all the numbers together, and all the variables

9y+27=0

We move all terms containing y to the left, all other terms to the right

9y=-27

y=-27/9

y=-3

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