-3(y-5)=6-(2y+2)

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Solution for -3(y-5)=6-(2y+2) equation: 



-3(y-5)=6-(2y+2)

We move all terms to the left:

-3(y-5)-(6-(2y+2))=0

We multiply parentheses

-3y-(6-(2y+2))+15=0



We calculate terms in parentheses: -(6-(2y+2)), so:

6-(2y+2)

determiningTheFunctionDomain
-(2y+2)+6

We get rid of parentheses

-2y-2+6

We add all the numbers together, and all the variables

-2y+4

Back to the equation:

-(-2y+4)



We get rid of parentheses

-3y+2y-4+15=0

We add all the numbers together, and all the variables

-1y+11=0

We move all terms containing y to the left, all other terms to the right

-y=-11

y=-11/-1

y=+11

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