-3(y-5y)+9=-2(2y-y)+6+13y

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Solution for -3(y-5y)+9=-2(2y-y)+6+13y equation: 



-3(y-5y)+9=-2(2y-y)+6+13y

We move all terms to the left:

-3(y-5y)+9-(-2(2y-y)+6+13y)=0

We add all the numbers together, and all the variables

-3(-4y)-(-2(+y)+6+13y)+9=0

We multiply parentheses

12y-(-2(+y)+6+13y)+9=0



We calculate terms in parentheses: -(-2(+y)+6+13y), so:

-2(+y)+6+13y

determiningTheFunctionDomain
-2(+y)+13y+6

We add all the numbers together, and all the variables

13y-2(+y)+6

We multiply parentheses

13y-2y+6

We add all the numbers together, and all the variables

11y+6

Back to the equation:

-(11y+6)



We get rid of parentheses

12y-11y-6+9=0

We add all the numbers together, and all the variables

y+3=0

We move all terms containing y to the left, all other terms to the right

y=-3

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