-3(y-6)=-8(-y-2)

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Solution for -3(y-6)=-8(-y-2) equation: 



-3(y-6)=-8(-y-2)

We move all terms to the left:

-3(y-6)-(-8(-y-2))=0

We add all the numbers together, and all the variables

-3(y-6)-(-8(-1y-2))=0

We multiply parentheses

-3y-(-8(-1y-2))+18=0



We calculate terms in parentheses: -(-8(-1y-2)), so:

-8(-1y-2)

We multiply parentheses

8y+16

Back to the equation:

-(8y+16)



We get rid of parentheses

-3y-8y-16+18=0

We add all the numbers together, and all the variables

-11y+2=0

We move all terms containing y to the left, all other terms to the right

-11y=-2

y=-2/-11

y=2/11

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