-3(z+2)-1=3(-2-4z)+5

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Solution for -3(z+2)-1=3(-2-4z)+5 equation: 



-3(+2)-1=3(-2-4Z)+5

We move all terms to the left:

-3(+2)-1-(3(-2-4Z)+5)=0

We add all the numbers together, and all the variables

-(3(-4Z-2)+5)-1-32=0

We add all the numbers together, and all the variables

-(3(-4Z-2)+5)-33=0



We calculate terms in parentheses: -(3(-4Z-2)+5), so:

3(-4Z-2)+5

We multiply parentheses

-12Z-6+5

We add all the numbers together, and all the variables

-12Z-1

Back to the equation:

-(-12Z-1)



We get rid of parentheses

12Z+1-33=0

We add all the numbers together, and all the variables

12Z-32=0

We move all terms containing Z to the left, all other terms to the right

12Z=32

Z=32/12

Z=2+2/3

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