-3(z+2)=2z-3

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Solution for -3(z+2)=2z-3 equation: 



-3(z+2)=2z-3

We move all terms to the left:

-3(z+2)-(2z-3)=0

We multiply parentheses

-3z-(2z-3)-6=0

We get rid of parentheses

-3z-2z+3-6=0

We add all the numbers together, and all the variables

-5z-3=0

We move all terms containing z to the left, all other terms to the right

-5z=3

z=3/-5

z=-3/5

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