-3(z-4)-(3-7z)=2(2z+1)

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Solution for -3(z-4)-(3-7z)=2(2z+1) equation:


Simplifying
-3(z + -4) + -1(3 + -7z) = 2(2z + 1)

Reorder the terms:
-3(-4 + z) + -1(3 + -7z) = 2(2z + 1)
(-4 * -3 + z * -3) + -1(3 + -7z) = 2(2z + 1)
(12 + -3z) + -1(3 + -7z) = 2(2z + 1)
12 + -3z + (3 * -1 + -7z * -1) = 2(2z + 1)
12 + -3z + (-3 + 7z) = 2(2z + 1)

Reorder the terms:
12 + -3 + -3z + 7z = 2(2z + 1)

Combine like terms: 12 + -3 = 9
9 + -3z + 7z = 2(2z + 1)

Combine like terms: -3z + 7z = 4z
9 + 4z = 2(2z + 1)

Reorder the terms:
9 + 4z = 2(1 + 2z)
9 + 4z = (1 * 2 + 2z * 2)
9 + 4z = (2 + 4z)

Add '-4z' to each side of the equation.
9 + 4z + -4z = 2 + 4z + -4z

Combine like terms: 4z + -4z = 0
9 + 0 = 2 + 4z + -4z
9 = 2 + 4z + -4z

Combine like terms: 4z + -4z = 0
9 = 2 + 0
9 = 2

Solving
9 = 2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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