-3*(3y-5)+2y+1=0

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Solution for -3*(3y-5)+2y+1=0 equation: 



-3(3y-5)+2y+1=0

We add all the numbers together, and all the variables

2y-3(3y-5)+1=0

We multiply parentheses

2y-9y+15+1=0

We add all the numbers together, and all the variables

-7y+16=0

We move all terms containing y to the left, all other terms to the right

-7y=-16

y=-16/-7

y=2+2/7

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