-3+(1/6y)-18=72

Solution for -3+(1/6y)-18=72 equation:

-3+(1/6y)-18=72

We move all terms to the left:

-3+(1/6y)-18-(72)=0


Domain of the equation: 6y)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

(+1/6y)-3-18-72=0

We add all the numbers together, and all the variables

(+1/6y)-93=0

We get rid of parentheses

1/6y-93=0

We multiply all the terms by the denominator


-93*6y+1=0

Wy multiply elements

-558y+1=0

We move all terms containing y to the left, all other terms to the right

-558y=-1

y=-1/-558

y=1/558