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-3+(2a-6)=5-5a-4(a+6)
We move all terms to the left:
-3+(2a-6)-(5-5a-4(a+6))=0
We get rid of parentheses
2a-(5-5a-4(a+6))-6-3=0
We calculate terms in parentheses: -(5-5a-4(a+6)), so:We add all the numbers together, and all the variables
5-5a-4(a+6)
determiningTheFunctionDomain -5a-4(a+6)+5
We multiply parentheses
-5a-4a-24+5
We add all the numbers together, and all the variables
-9a-19
Back to the equation:
-(-9a-19)
2a-(-9a-19)-9=0
We get rid of parentheses
2a+9a+19-9=0
We add all the numbers together, and all the variables
11a+10=0
We move all terms containing a to the left, all other terms to the right
11a=-10
a=-10/11
a=-10/11
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