-3+2(3+p)=13

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Solution for -3+2(3+p)=13 equation: 



-3+2(3+p)=13

We move all terms to the left:

-3+2(3+p)-(13)=0

We add all the numbers together, and all the variables

2(p+3)-3-13=0

We add all the numbers together, and all the variables

2(p+3)-16=0

We multiply parentheses

2p+6-16=0

We add all the numbers together, and all the variables

2p-10=0

We move all terms containing p to the left, all other terms to the right

2p=10

p=10/2

p=5

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