-3+2/3(6n-42)=51

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Solution for -3+2/3(6n-42)=51 equation: 



-3+2/3(6n-42)=51

We move all terms to the left:

-3+2/3(6n-42)-(51)=0



Domain of the equation: 3(6n-42)!=0

n∈R



We add all the numbers together, and all the variables

2/3(6n-42)-54=0

We multiply all the terms by the denominator


-54*3(6n-42)+2=0

Wy multiply elements

-162n(6+2=0

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