-3+3x-4=6(x+2)+8

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Solution for -3+3x-4=6(x+2)+8 equation: 



-3+3x-4=6(x+2)+8

We move all terms to the left:

-3+3x-4-(6(x+2)+8)=0

We add all the numbers together, and all the variables

3x-(6(x+2)+8)-7=0



We calculate terms in parentheses: -(6(x+2)+8), so:

6(x+2)+8

We multiply parentheses

6x+12+8

We add all the numbers together, and all the variables

6x+20

Back to the equation:

-(6x+20)



We get rid of parentheses

3x-6x-20-7=0

We add all the numbers together, and all the variables

-3x-27=0

We move all terms containing x to the left, all other terms to the right

-3x=27

x=27/-3

x=-9

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