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-3+4/5X=5X
We move all terms to the left:
-3+4/5X-(5X)=0
Domain of the equation: 5X!=0We add all the numbers together, and all the variables
X!=0/5
X!=0
X∈R
-5X+4/5X-3=0
We multiply all the terms by the denominator
-5X*5X-3*5X+4=0
Wy multiply elements
-25X^2-15X+4=0
a = -25; b = -15; c = +4;
Δ = b2-4ac
Δ = -152-4·(-25)·4
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-25}{2*-25}=\frac{-10}{-50} =1/5 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+25}{2*-25}=\frac{40}{-50} =-4/5 $
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