-3+4b=3(b-1)+5

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Solution for -3+4b=3(b-1)+5 equation: 



-3+4b=3(b-1)+5

We move all terms to the left:

-3+4b-(3(b-1)+5)=0



We calculate terms in parentheses: -(3(b-1)+5), so:

3(b-1)+5

We multiply parentheses

3b-3+5

We add all the numbers together, and all the variables

3b+2

Back to the equation:

-(3b+2)



We get rid of parentheses

4b-3b-2-3=0

We add all the numbers together, and all the variables

b-5=0

We move all terms containing b to the left, all other terms to the right

b=5

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