-3+5(b+4)+4(b+3)=2

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Solution for -3+5(b+4)+4(b+3)=2 equation:


Simplifying
-3 + 5(b + 4) + 4(b + 3) = 2

Reorder the terms:
-3 + 5(4 + b) + 4(b + 3) = 2
-3 + (4 * 5 + b * 5) + 4(b + 3) = 2
-3 + (20 + 5b) + 4(b + 3) = 2

Reorder the terms:
-3 + 20 + 5b + 4(3 + b) = 2
-3 + 20 + 5b + (3 * 4 + b * 4) = 2
-3 + 20 + 5b + (12 + 4b) = 2

Reorder the terms:
-3 + 20 + 12 + 5b + 4b = 2

Combine like terms: -3 + 20 = 17
17 + 12 + 5b + 4b = 2

Combine like terms: 17 + 12 = 29
29 + 5b + 4b = 2

Combine like terms: 5b + 4b = 9b
29 + 9b = 2

Solving
29 + 9b = 2

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-29' to each side of the equation.
29 + -29 + 9b = 2 + -29

Combine like terms: 29 + -29 = 0
0 + 9b = 2 + -29
9b = 2 + -29

Combine like terms: 2 + -29 = -27
9b = -27

Divide each side by '9'.
b = -3

Simplifying
b = -3

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