-3+t=2(1+3t)

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Solution for -3+t=2(1+3t) equation: 



-3+t=2(1+3t)

We move all terms to the left:

-3+t-(2(1+3t))=0

We add all the numbers together, and all the variables

t-(2(3t+1))-3=0



We calculate terms in parentheses: -(2(3t+1)), so:

2(3t+1)

We multiply parentheses

6t+2

Back to the equation:

-(6t+2)



We get rid of parentheses

t-6t-2-3=0

We add all the numbers together, and all the variables

-5t-5=0

We move all terms containing t to the left, all other terms to the right

-5t=5

t=5/-5

t=-1

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