-3+x2=550

Solution for -3+x2=550 equation:

-3+x2=550

We move all terms to the left:

-3+x2-(550)=0

We add all the numbers together, and all the variables

x^2-553=0

a = 1; b = 0; c = -553;
Δ = b2-4ac
Δ = 02-4·1·(-553)
Δ = 2212
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2212}=\sqrt{4*553}=\sqrt{4}*\sqrt{553}=2\sqrt{553}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{553}}{2*1}=\frac{0-2\sqrt{553}}{2}
=-\frac{2\sqrt{553}}{2}
=-\sqrt{553}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{553}}{2*1}=\frac{0+2\sqrt{553}}{2}
=\frac{2\sqrt{553}}{2}
=\sqrt{553}
$