-3+x=-3/5x+5

Solution for -3+x=-3/5x+5 equation:

-3+x=-3/5x+5

We move all terms to the left:

-3+x-(-3/5x+5)=0


Domain of the equation: 5x+5)!=0

x∈R


We get rid of parentheses

x+3/5x-5-3=0

We multiply all the terms by the denominator


x*5x-5*5x-3*5x+3=0

Wy multiply elements

5x^2-25x-15x+3=0

We add all the numbers together, and all the variables

5x^2-40x+3=0

a = 5; b = -40; c = +3;
Δ = b2-4ac
Δ = -402-4·5·3
Δ = 1540
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1540}=\sqrt{4*385}=\sqrt{4}*\sqrt{385}=2\sqrt{385}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-2\sqrt{385}}{2*5}=\frac{40-2\sqrt{385}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+2\sqrt{385}}{2*5}=\frac{40+2\sqrt{385}}{10}
$