-3-(4x-1)=1+7(x-2)

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Solution for -3-(4x-1)=1+7(x-2) equation: 



-3-(4x-1)=1+7(x-2)

We move all terms to the left:

-3-(4x-1)-(1+7(x-2))=0

We get rid of parentheses

-4x-(1+7(x-2))+1-3=0



We calculate terms in parentheses: -(1+7(x-2)), so:

1+7(x-2)

determiningTheFunctionDomain
7(x-2)+1

We multiply parentheses

7x-14+1

We add all the numbers together, and all the variables

7x-13

Back to the equation:

-(7x-13)



We add all the numbers together, and all the variables

-4x-(7x-13)-2=0

We get rid of parentheses

-4x-7x+13-2=0

We add all the numbers together, and all the variables

-11x+11=0

We move all terms containing x to the left, all other terms to the right

-11x=-11

x=-11/-11

x=1

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