-3-(5/(u+5))=-5/((u+2)(u+5))

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Solution for -3-(5/(u+5))=-5/((u+2)(u+5)) equation: 


D( u )

(u+2)*(u+5) = 0

u+5 = 0

(u+2)*(u+5) = 0

(u+2)*(u+5) = 0

( u+2 )

u+2 = 0 // - 2

u = -2

( u+5 )

u+5 = 0 // - 5

u = -5

u+5 = 0

u+5 = 0

u+5 = 0 // - 5

u = -5

u in (-oo:-5) U (-5:-2) U (-2:+oo)

-(5/(u+5))-3 = -5/((u+2)*(u+5)) // + -5/((u+2)*(u+5))

-(5/(u+5))-(-5/((u+2)*(u+5)))-3 = 0

5*(u+5)^-1*(u+2)^-1-5*(u+5)^-1-3 = 0

5/((u+5)*(u+2))-5/(u+5)-3 = 0

5/(u+5)-5/(u+5)+(-3*(u+5))/(u+5) = 0

5-3*(u+5)-5 = 0

-3*u-15 = 0

(-3*u-15)/(u+5) = 0

(-3*u-15)/(u+5) = 0 // * u+5

-3*u-15 = 0

-3*u-15 = 0 // + 15

-3*u = 15 // : -3

u = 15/(-3)

u = -5

u in { -5} 

u belongs to the empty set

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