-3-+3n=2(n+3)-2n

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Solution for -3-+3n=2(n+3)-2n equation: 



-3-+3n=2(n+3)-2n

We move all terms to the left:

-3-+3n-(2(n+3)-2n)=0

We add all the numbers together, and all the variables

3n-(2(n+3)-2n)=0



We calculate terms in parentheses: -(2(n+3)-2n), so:

2(n+3)-2n

We add all the numbers together, and all the variables

-2n+2(n+3)

We multiply parentheses

-2n+2n+6

We add all the numbers together, and all the variables

6

Back to the equation:

-(6)



We move all terms containing n to the left, all other terms to the right

3n=6

n=6/3

n=2

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