-3-2(2-3b)=5(b-4)-3

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Solution for -3-2(2-3b)=5(b-4)-3 equation: 



-3-2(2-3b)=5(b-4)-3

We move all terms to the left:

-3-2(2-3b)-(5(b-4)-3)=0

We add all the numbers together, and all the variables

-2(-3b+2)-(5(b-4)-3)-3=0

We multiply parentheses

6b-(5(b-4)-3)-4-3=0



We calculate terms in parentheses: -(5(b-4)-3), so:

5(b-4)-3

We multiply parentheses

5b-20-3

We add all the numbers together, and all the variables

5b-23

Back to the equation:

-(5b-23)



We add all the numbers together, and all the variables

6b-(5b-23)-7=0

We get rid of parentheses

6b-5b+23-7=0

We add all the numbers together, and all the variables

b+16=0

We move all terms containing b to the left, all other terms to the right

b=-16

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