-3-2(3k+4)=3k+7

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Solution for -3-2(3k+4)=3k+7 equation: 



-3-2(3k+4)=3k+7

We move all terms to the left:

-3-2(3k+4)-(3k+7)=0

We multiply parentheses

-6k-(3k+7)-8-3=0

We get rid of parentheses

-6k-3k-7-8-3=0

We add all the numbers together, and all the variables

-9k-18=0

We move all terms containing k to the left, all other terms to the right

-9k=18

k=18/-9

k=-2

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