-3-2/u-7=7/(u=1)(u-7)

Solution for -3-2/u-7=7/(u=1)(u-7) equation:

-3-2/u-7=7/(u=1)(u-7)

We move all terms to the left:

-3-2/u-7-(7/(u)=0


Domain of the equation: u!=0

u∈R



Domain of the equation: u-3-7!=0

We move all terms containing u to the left, all other terms to the right

u!=10

u∈R


We calculate fractions


(-2u-10)/(u^2-10)+(-(7*u)/(u^2-10)=0


We calculate terms in parentheses: +(-(7*u)/(u^2-10), so:

-(7*u)/(u^2-10

We add all the numbers together, and all the variables

-(+7u)/(u^2-10

We multiply all the terms by the denominator


-(+7u)

We get rid of parentheses

-7u

Back to the equation:

+(-7u)


We get rid of parentheses

(-2u-10)/(u^2-10)-7u=0

We multiply all the terms by the denominator


(-2u-10)-7u*(u^2-10)=0

We multiply parentheses

-7u^3+(-2u-10)+70u=0

We get rid of parentheses

-7u^3-2u+70u-10=0

We do not support eupression: u^3