-3-4(t-5)=2(3-t)+11

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Solution for -3-4(t-5)=2(3-t)+11 equation: 



-3-4(t-5)=2(3-t)+11

We move all terms to the left:

-3-4(t-5)-(2(3-t)+11)=0

We add all the numbers together, and all the variables

-4(t-5)-(2(-1t+3)+11)-3=0

We multiply parentheses

-4t-(2(-1t+3)+11)+20-3=0



We calculate terms in parentheses: -(2(-1t+3)+11), so:

2(-1t+3)+11

We multiply parentheses

-2t+6+11

We add all the numbers together, and all the variables

-2t+17

Back to the equation:

-(-2t+17)



We add all the numbers together, and all the variables

-4t-(-2t+17)+17=0

We get rid of parentheses

-4t+2t-17+17=0

We add all the numbers together, and all the variables

-2t=0

t=0/-2

t=0

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